x^2-23x^2+49=0

Solution for x^2-23x^2+49=0 equation:

x^2-23x^2+49=0

We add all the numbers together, and all the variables

-22x^2+49=0

a = -22; b = 0; c = +49;
Δ = b2-4ac
Δ = 02-4·(-22)·49
Δ = 4312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4312}=\sqrt{196*22}=\sqrt{196}*\sqrt{22}=14\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{22}}{2*-22}=\frac{0-14\sqrt{22}}{-44}
=-\frac{14\sqrt{22}}{-44}
=-\frac{7\sqrt{22}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{22}}{2*-22}=\frac{0+14\sqrt{22}}{-44}
=\frac{14\sqrt{22}}{-44}
=\frac{7\sqrt{22}}{-22}
$